##### From: MatthewRe: GAMSAT Chemistry Questions

Below is a series of sample GAMSAT General Chemistry Questions which are just like the questions in the actual exam.

Our GAMSAT Study Package contains a complete practice test, which contains questions just like these.

Now, we’ll get started.

### GAMSAT General Chemistry Questions

(Do NOT use a calculator)

Unit 1
Question 1-3

The thermodynamic properties of an ideal gas are described by the following equation of state:

P x V = n x R x T

where:

P is the pressure (atm)
V is the volume (L)
n is the amount of gas (mol)
R is the universal gas constant (0.082 L atm/K mol)
T is the temperature (K)

1. Which of the following values better approximate the volume of 0.1 moles of gas at P = 1 atm and room temperature (ca. 300 K)?

A. 0.3 L.
B. 3 L.
C. 30 L.
D. 300 L.

2. A gas is maintained at 200 K and 2 atm in a closed vessel. How many moles are kept in the small 10 mL container?

A. 10-1 mol.
B. 10-2 mol.
C. 10-3 mol.
D. 10-4 mol.

3. The volume of a gas (5 g), measured at 300 K and 3 atm, is 0.5 L. What is the molecular weight of this chemical species?

A. 10 g/mol.
B. 30 g/mol.
C. 100 g/mol.
D. 300 g/mol. ### Answers To GAMSAT General Chemistry Questions

From the above equation,

V = (n x R x T)/P = (0.1 mol x 0.082 L atm/K mol x 300 K)/ 1 atm ≌ 0.1 x 0.1 x 300 = 3 L

The key is therefore B.

From the above equation,

n = (P x V)/R x T = (2 atm x 0.01 L)/ 0.082 L atm/K mol x 200 K ≌

≌ (2 x 0.01)/ (0.1 x 200) = 1 mmol

The key is therefore C.

From the above equation,

n = (P x V)/R x T = (3 atm x 0.5 L)/ 0.082 L atm/K mol x 300 K ≌

≌ (3 x 0.5)/ (0.1 x 300) = 0.05 mmol

Also:

n = mass (g) / molecular weight (g/mol) = 5 g / MW = 0.05 mol

Hence:

MW = mass/n = 5 / 0.05 = 100 g/mol

The key is therefore C.

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